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2p^2-108-6p=0
a = 2; b = -6; c = -108;
Δ = b2-4ac
Δ = -62-4·2·(-108)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*2}=\frac{-24}{4} =-6 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*2}=\frac{36}{4} =9 $
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